Optimal. Leaf size=52 \[ \frac{\tan (c+d x)}{b d}-\frac{(a-b) \tan ^{-1}\left (\frac{\sqrt{b} \tan (c+d x)}{\sqrt{a}}\right )}{\sqrt{a} b^{3/2} d} \]
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Rubi [A] time = 0.0673449, antiderivative size = 52, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.13, Rules used = {3675, 388, 205} \[ \frac{\tan (c+d x)}{b d}-\frac{(a-b) \tan ^{-1}\left (\frac{\sqrt{b} \tan (c+d x)}{\sqrt{a}}\right )}{\sqrt{a} b^{3/2} d} \]
Antiderivative was successfully verified.
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Rule 3675
Rule 388
Rule 205
Rubi steps
\begin{align*} \int \frac{\sec ^4(c+d x)}{a+b \tan ^2(c+d x)} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{1+x^2}{a+b x^2} \, dx,x,\tan (c+d x)\right )}{d}\\ &=\frac{\tan (c+d x)}{b d}-\frac{(a-b) \operatorname{Subst}\left (\int \frac{1}{a+b x^2} \, dx,x,\tan (c+d x)\right )}{b d}\\ &=-\frac{(a-b) \tan ^{-1}\left (\frac{\sqrt{b} \tan (c+d x)}{\sqrt{a}}\right )}{\sqrt{a} b^{3/2} d}+\frac{\tan (c+d x)}{b d}\\ \end{align*}
Mathematica [A] time = 0.143639, size = 52, normalized size = 1. \[ \frac{\tan (c+d x)}{b d}-\frac{(a-b) \tan ^{-1}\left (\frac{\sqrt{b} \tan (c+d x)}{\sqrt{a}}\right )}{\sqrt{a} b^{3/2} d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.063, size = 66, normalized size = 1.3 \begin{align*}{\frac{\tan \left ( dx+c \right ) }{bd}}-{\frac{a}{bd}\arctan \left ({b\tan \left ( dx+c \right ){\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}}+{\frac{1}{d}\arctan \left ({b\tan \left ( dx+c \right ){\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.62674, size = 644, normalized size = 12.38 \begin{align*} \left [\frac{\sqrt{-a b}{\left (a - b\right )} \cos \left (d x + c\right ) \log \left (\frac{{\left (a^{2} + 6 \, a b + b^{2}\right )} \cos \left (d x + c\right )^{4} - 2 \,{\left (3 \, a b + b^{2}\right )} \cos \left (d x + c\right )^{2} + 4 \,{\left ({\left (a + b\right )} \cos \left (d x + c\right )^{3} - b \cos \left (d x + c\right )\right )} \sqrt{-a b} \sin \left (d x + c\right ) + b^{2}}{{\left (a^{2} - 2 \, a b + b^{2}\right )} \cos \left (d x + c\right )^{4} + 2 \,{\left (a b - b^{2}\right )} \cos \left (d x + c\right )^{2} + b^{2}}\right ) + 4 \, a b \sin \left (d x + c\right )}{4 \, a b^{2} d \cos \left (d x + c\right )}, \frac{\sqrt{a b}{\left (a - b\right )} \arctan \left (\frac{{\left ({\left (a + b\right )} \cos \left (d x + c\right )^{2} - b\right )} \sqrt{a b}}{2 \, a b \cos \left (d x + c\right ) \sin \left (d x + c\right )}\right ) \cos \left (d x + c\right ) + 2 \, a b \sin \left (d x + c\right )}{2 \, a b^{2} d \cos \left (d x + c\right )}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sec ^{4}{\left (c + d x \right )}}{a + b \tan ^{2}{\left (c + d x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.65045, size = 84, normalized size = 1.62 \begin{align*} -\frac{\frac{{\left (\pi \left \lfloor \frac{d x + c}{\pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (b\right ) + \arctan \left (\frac{b \tan \left (d x + c\right )}{\sqrt{a b}}\right )\right )}{\left (a - b\right )}}{\sqrt{a b} b} - \frac{\tan \left (d x + c\right )}{b}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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